3.45 \(\int \frac {x}{(a+b \sec ^{-1}(c x))^3} \, dx\)
Optimal. Leaf size=15 \[ \text {Int}\left (\frac {x}{\left (a+b \sec ^{-1}(c x)\right )^3},x\right ) \]
[Out]
Unintegrable(x/(a+b*arcsec(c*x))^3,x)
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Rubi [A] time = 0.01, antiderivative size = 0, normalized size of antiderivative = 0.00,
number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used =
{} \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^3} \, dx \]
Verification is Not applicable to the result.
[In]
Int[x/(a + b*ArcSec[c*x])^3,x]
[Out]
Defer[Int][x/(a + b*ArcSec[c*x])^3, x]
Rubi steps
\begin {align*} \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^3} \, dx &=\int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^3} \, dx\\ \end {align*}
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Mathematica [A] time = 3.68, size = 0, normalized size = 0.00 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^3} \, dx \]
Verification is Not applicable to the result.
[In]
Integrate[x/(a + b*ArcSec[c*x])^3,x]
[Out]
Integrate[x/(a + b*ArcSec[c*x])^3, x]
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fricas [A] time = 0.49, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {x}{b^{3} \operatorname {arcsec}\left (c x\right )^{3} + 3 \, a b^{2} \operatorname {arcsec}\left (c x\right )^{2} + 3 \, a^{2} b \operatorname {arcsec}\left (c x\right ) + a^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x/(a+b*arcsec(c*x))^3,x, algorithm="fricas")
[Out]
integral(x/(b^3*arcsec(c*x)^3 + 3*a*b^2*arcsec(c*x)^2 + 3*a^2*b*arcsec(c*x) + a^3), x)
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x/(a+b*arcsec(c*x))^3,x, algorithm="giac")
[Out]
Timed out
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maple [A] time = 2.55, size = 0, normalized size = 0.00 \[ \int \frac {x}{\left (a +b \,\mathrm {arcsec}\left (c x \right )\right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(x/(a+b*arcsec(c*x))^3,x)
[Out]
int(x/(a+b*arcsec(c*x))^3,x)
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maxima [A] time = 0.00, size = 0, normalized size = 0.00 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x/(a+b*arcsec(c*x))^3,x, algorithm="maxima")
[Out]
-(24*(a*b^2*c^2*log(c)^2 + a^3*c^2)*x^4 + 8*(3*b^3*c^2*x^4 - 2*b^3*x^2)*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^3
- 16*(a*b^2*log(c)^2 + a^3)*x^2 + 24*(3*a*b^2*c^2*x^4 - 2*a*b^2*x^2)*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^2 + 2
*(3*a*b^2*c^2*x^4 - 2*a*b^2*x^2)*log(c^2*x^2)^2 + 8*(3*a*b^2*c^2*x^4 - 2*a*b^2*x^2)*log(x)^2 + 2*(4*b^3*x^2*ar
ctan(sqrt(c*x + 1)*sqrt(c*x - 1))^2 - b^3*x^2*log(c^2*x^2)^2 - 8*b^3*x^2*log(c)*log(x) - 4*b^3*x^2*log(x)^2 +
8*a*b^2*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1)) - 4*(b^3*log(c)^2 - a^2*b)*x^2 + 4*(b^3*x^2*log(c) + b^3*x^2*l
og(x))*log(c^2*x^2))*sqrt(c*x + 1)*sqrt(c*x - 1) + 2*(12*(b^3*c^2*log(c)^2 + 3*a^2*b*c^2)*x^4 - 8*(b^3*log(c)^
2 + 3*a^2*b)*x^2 + (3*b^3*c^2*x^4 - 2*b^3*x^2)*log(c^2*x^2)^2 + 4*(3*b^3*c^2*x^4 - 2*b^3*x^2)*log(x)^2 - 4*(3*
b^3*c^2*x^4*log(c) - 2*b^3*x^2*log(c) + (3*b^3*c^2*x^4 - 2*b^3*x^2)*log(x))*log(c^2*x^2) + 8*(3*b^3*c^2*x^4*lo
g(c) - 2*b^3*x^2*log(c))*log(x))*arctan(sqrt(c*x + 1)*sqrt(c*x - 1)) - (16*b^6*arctan(sqrt(c*x + 1)*sqrt(c*x -
1))^4 + b^6*log(c^2*x^2)^4 + 16*b^6*log(c)^4 + 64*b^6*log(c)*log(x)^3 + 16*b^6*log(x)^4 + 64*a*b^5*arctan(sqr
t(c*x + 1)*sqrt(c*x - 1))^3 + 32*a^2*b^4*log(c)^2 + 16*a^4*b^2 - 8*(b^6*log(c) + b^6*log(x))*log(c^2*x^2)^3 +
8*(b^6*log(c^2*x^2)^2 + 4*b^6*log(c)^2 + 8*b^6*log(c)*log(x) + 4*b^6*log(x)^2 + 12*a^2*b^4 - 4*(b^6*log(c) + b
^6*log(x))*log(c^2*x^2))*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^2 + 8*(3*b^6*log(c)^2 + 6*b^6*log(c)*log(x) + 3*b
^6*log(x)^2 + a^2*b^4)*log(c^2*x^2)^2 + 32*(3*b^6*log(c)^2 + a^2*b^4)*log(x)^2 + 16*(a*b^5*log(c^2*x^2)^2 + 4*
a*b^5*log(c)^2 + 8*a*b^5*log(c)*log(x) + 4*a*b^5*log(x)^2 + 4*a^3*b^3 - 4*(a*b^5*log(c) + a*b^5*log(x))*log(c^
2*x^2))*arctan(sqrt(c*x + 1)*sqrt(c*x - 1)) - 32*(b^6*log(c)^3 + 3*b^6*log(c)*log(x)^2 + b^6*log(x)^3 + a^2*b^
4*log(c) + (3*b^6*log(c)^2 + a^2*b^4)*log(x))*log(c^2*x^2) + 64*(b^6*log(c)^3 + a^2*b^4*log(c))*log(x))*integr
ate(8*(3*a*c^2*x^3 - a*x + (3*b*c^2*x^3 - b*x)*arctan(sqrt(c*x + 1)*sqrt(c*x - 1)))/(4*b^4*arctan(sqrt(c*x + 1
)*sqrt(c*x - 1))^2 + b^4*log(c^2*x^2)^2 + 4*b^4*log(c)^2 + 8*b^4*log(c)*log(x) + 4*b^4*log(x)^2 + 8*a*b^3*arct
an(sqrt(c*x + 1)*sqrt(c*x - 1)) + 4*a^2*b^2 - 4*(b^4*log(c) + b^4*log(x))*log(c^2*x^2)), x) - 8*(3*a*b^2*c^2*x
^4*log(c) - 2*a*b^2*x^2*log(c) + (3*a*b^2*c^2*x^4 - 2*a*b^2*x^2)*log(x))*log(c^2*x^2) + 16*(3*a*b^2*c^2*x^4*lo
g(c) - 2*a*b^2*x^2*log(c))*log(x))/(16*b^6*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^4 + b^6*log(c^2*x^2)^4 + 16*b^6
*log(c)^4 + 64*b^6*log(c)*log(x)^3 + 16*b^6*log(x)^4 + 64*a*b^5*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^3 + 32*a^2
*b^4*log(c)^2 + 16*a^4*b^2 - 8*(b^6*log(c) + b^6*log(x))*log(c^2*x^2)^3 + 8*(b^6*log(c^2*x^2)^2 + 4*b^6*log(c)
^2 + 8*b^6*log(c)*log(x) + 4*b^6*log(x)^2 + 12*a^2*b^4 - 4*(b^6*log(c) + b^6*log(x))*log(c^2*x^2))*arctan(sqrt
(c*x + 1)*sqrt(c*x - 1))^2 + 8*(3*b^6*log(c)^2 + 6*b^6*log(c)*log(x) + 3*b^6*log(x)^2 + a^2*b^4)*log(c^2*x^2)^
2 + 32*(3*b^6*log(c)^2 + a^2*b^4)*log(x)^2 + 16*(a*b^5*log(c^2*x^2)^2 + 4*a*b^5*log(c)^2 + 8*a*b^5*log(c)*log(
x) + 4*a*b^5*log(x)^2 + 4*a^3*b^3 - 4*(a*b^5*log(c) + a*b^5*log(x))*log(c^2*x^2))*arctan(sqrt(c*x + 1)*sqrt(c*
x - 1)) - 32*(b^6*log(c)^3 + 3*b^6*log(c)*log(x)^2 + b^6*log(x)^3 + a^2*b^4*log(c) + (3*b^6*log(c)^2 + a^2*b^4
)*log(x))*log(c^2*x^2) + 64*(b^6*log(c)^3 + a^2*b^4*log(c))*log(x))
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mupad [A] time = 0.00, size = -1, normalized size = -0.07 \[ \int \frac {x}{{\left (a+b\,\mathrm {acos}\left (\frac {1}{c\,x}\right )\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(x/(a + b*acos(1/(c*x)))^3,x)
[Out]
int(x/(a + b*acos(1/(c*x)))^3, x)
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sympy [A] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{\left (a + b \operatorname {asec}{\left (c x \right )}\right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x/(a+b*asec(c*x))**3,x)
[Out]
Integral(x/(a + b*asec(c*x))**3, x)
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